Lesson 2 of 11

Combustion Fundamentals

The physics of the flame itself: equivalence ratio, the bell-shaped flame-temperature curve, why Arrhenius makes temperature the master variable, and the deep difference between premixed and diffusion flames.

9 min3 live simulations
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The question

Why does a change of just a few hundred kelvin decide whether a combustor is stable, efficient, clean or melting?

By the end of this lesson you should be able to see the answer: one curve, one exponential, and the way they combine.

Counting atoms: the equivalence ratio

Burning is bookkeeping. For a kerosene-like fuel, one idealised molecule needs a fixed amount of oxygen to become carbon dioxide and water:

C12H23+17.75 O2  ⟶  12 CO2+11.5 H2O\mathrm{C_{12}H_{23}} + 17.75\,\mathrm{O_2} \;\longrightarrow\; 12\,\mathrm{CO_2} + 11.5\,\mathrm{H_2O}

Because air is mostly nitrogen, that works out to a StoichiometricThe exact mixture in which every fuel molecule finds just enough oxygen to burn completely — about 1 kg of kerosene per 14.7 kg of air. fuel–air mass ratio of about 0.068, roughly one kilogram of fuel for every 14.7 kg of air. Any real mixture is described relative to that perfect ratio by the Equivalence ratio φActual fuel–air ratio divided by the stoichiometric one. Below 1 is lean (spare air), above 1 is rich (spare fuel)., written in fuel gold throughout the course:

ϕ=(F/A)actual(F/A)stoichiometric\cfuel{\phi} = \frac{(F/A)_\text{actual}}{(F/A)_\text{stoichiometric}}

  • ϕ<1\phi < 1: lean. There is more oxygen than the fuel can use; the spare air just gets heated.
  • ϕ=1\phi = 1: stoichiometric. Every atom finds a partner.
  • ϕ>1\phi > 1: rich. Not enough oxygen, so some fuel leaves as CO, H₂ or soot.

That single number will be on the axis of almost every plot for the rest of the course.

The master curve

Now ask: if the mixture burns completely, with no heat lost, how hot does it get? That is the Adiabatic flame temperatureThe temperature a mixture reaches if it burns completely with no heat lost. A bell-shaped function of φ, peaking slightly rich. Tad\cflame{T_{ad}}. Here it is as a function of ϕ\cfuel{\phi}, and it is worth spending a few minutes playing with.

ExploreThe master curve: flame temperature vs. equivalence ratio
TOO LEANstoichiometric0.511.522.5350010001500200025003000equivalence ratio φadiabatic flame temperature (K)10⁻⁴10⁻²10⁰10²relative NOₓ formation rate (log)2011 K
0.80
lean: excess air
300 K
Idle ≈ 450 K · take-off ≈ 850 K
Where do the atoms go?
burned → CO₂ + H₂O
fuel supplied ∝ 0.80 × stoichiometric · fuel–air ratio by mass = 0.054
Flame temperature2011 K
Relative NOₓ rate1.21×vs. 2000 K lean flame
Flammable?Yeslimits φ ≈ 0.50 – 3.0
Challenges0/3
  • Find the hottest mixture of all. Is it exactly stoichiometric?
  • Make a φ = 0.42 mixture burnable — without adding fuel.
  • Find a flammable mixture that makes 1000× less NOₓ than the 2000 K reference.
Drag across the plot to change φ. Watch the purple NOₓ curve — on a logarithmic axis — respond to a few hundred kelvin.
Going deeper
Where the bell comes from: a back-of-envelope flame temperature

For a lean mixture, all the fuel burns. Per kilogram of mixture, the fuel mass fraction is f=0.068 ϕ1+0.068 ϕf = \frac{0.068\,\phi}{1 + 0.068\,\phi}, and it releases f⋅LHVf \cdot \text{LHV} of heat into gas with specific heat cˉp≈1.25\bar c_p \approx 1.25 kJ/kg·K:

Tad≈T3+f LHVcˉpT_{ad} \approx T_3 + \frac{f\,\text{LHV}}{\bar c_p}

At ϕ=1\phi = 1 that gives a rise of about 0.064×43 200/1.25≈22000.064 \times 43\,200 / 1.25 \approx 2200 K, a slight overestimate, because at these temperatures cpc_p grows and some CO₂ and H₂O dissociate, soaking up energy. For ϕ>1\phi > 1 the heat release is capped by the oxygen (it stays at the ϕ=1\phi = 1 value) while the extra fuel adds mass to heat, so the temperature falls. Linear rise, oxygen-capped plateau, dilution by excess fuel: that is the bell.

Three things to notice, because each one echoes through the whole course.

It's a bell, peaked just rich of stoichiometric. On the lean side, adding fuel adds heat to the same mass of gas, so the temperature climbs. On the rich side there isn't enough oxygen to release the extra fuel's energy, but the unburned fuel still has to be heated, so temperature falls. The peak sits slightly rich (φ ≈ 1.05), partly because of dissociation: at these temperatures some CO₂ and H₂O split apart and soak up energy.

The inlet temperature lifts the whole curve. A modern engine compresses air to 800–900 K before it ever meets fuel. That preheat adds almost directly to the flame temperature, which is why high-pressure-ratio engines are both more efficient and harder to keep clean.

Look at the purple curve. Thermal NOₓ formation spans many powers of ten across a range where the temperature changes by only a few hundred kelvin. That is not a quirk of NOₓ. It is what every chemical rate does, and the next widget shows why.

Arrhenius: why temperature is the master variable

Molecules in a gas are not all equally energetic. Their collision energies spread out in a distribution, and only the rare collisions in the far tail, those energetic enough to break the right bonds, actually react. The energy needed is the Activation energy EₐThe energy barrier a collision must overcome for a reaction to happen. EaE_a.

Heat the gas and the whole distribution stretches to the right. The bulk barely changes, but the tiny tail above EaE_a fattens enormously:

ExploreWhy a few hundred kelvin changes everything
050100150200molecular collision energy (kJ/mol)Eₐ = 125 kJ/molred tail shown ×10³dashed: 1000 K
500100015002000250010⁻¹⁵10⁻⁵10⁵10¹⁵temperature (K)reaction rate relative to 1000 K (log scale)
1500 K
125 kJ/mol
Hydrocarbon global ≈ 125 · Zeldovich NO ≈ 575
Fraction above Eₐ1.7×10⁻⁴
Rate vs 1000 K124×
Barrier height10.0Eₐ / RT: barrier in units of thermal energy
Challenges0/2
  • Make the hydrocarbon reaction (Eₐ ≈ 125) run 1000× faster than at 1000 K.
  • Set the barrier to the NO value (~575 kJ/mol) and heat to 2000 K. How many times faster than at 1000 K?
Molecules in a gas have a spread of energies. Only those in the far tail — above the activation barrier Eₐ — can react. Heating the gas fattens that tail exponentially.

The fraction of collisions above the barrier behaves, to an excellent approximation, like e−Ea/RTe^{-E_a/RT}. That is the Arrhenius lawReaction rate ∝ exp(−Eₐ/RT): only molecules in the energetic tail can react, so rates grow exponentially with temperature., with the temperature in flame red:

ω˙  ∝  exp⁡ ⁣(−EaR T)\dot{\omega} \;\propto\; \exp\!\left(-\frac{E_a}{R\,\cflame{T}}\right)

The key quantity is Ea/RTE_a/RT: how many "thermal energies" tall the barrier is. When it is around 10, every 10% rise in temperature multiplies the rate by roughly e1≈2.5e^{1}\approx 2.5. For the Zeldovich reaction that makes NO, Ea/RTE_a/RT is closer to 35 at flame temperatures. That is why NOₓ, in the explorer above, lives on a logarithmic axis.

Estimate first
For a typical hydrocarbon reaction (Eₐ ≈ 125 kJ/mol), how many times faster does it run at 2000 K than at 1000 K?
1101001,00010,000100,0001,000,000
Drag along the line to place your guess — each tick is ten times the last.

This one idea explains a surprising amount of combustor behaviour:

  • Cold starts are hard: well-mixed but cold fuel and air simply don't react fast enough.
  • Altitude relight is hard: thin, cold air lowers both temperature and collision rate.
  • The primary zone must run hot: to finish the chemistry within a few milliseconds of residence time.
  • NOₓ is almost purely a temperature problem: Lesson 9 is built on this.
Check your intuition
A reaction has Eₐ/RT = 20 at 1500 K. Roughly how much faster does it run at 1650 K (10% hotter)?

Two kinds of flame

There is a second fundamental choice, and it shapes every low-emissions strategy in Lesson 9: are fuel and air mixed before they burn, or do they meet in the flame?

CompareTwo kinds of flame
premixed fuel + air, U = 2.0 m/sα = 11.5°
1.00
2.00 m/s
Flame speed0.40 m/s
Cone angle11.5°
Stable cone. Try making the mixture leaner — S_L falls, and the cone grows taller to compensate.
Challenges0/3
  • Make the premixed flame flash back into the tube.
  • Stretch the cone to an angle under 6° — without touching the flow speed. (Hint: the mixture.)
  • Lift the flame off the burner rim.
A premixed flame is a wave travelling into the mixture at the flame speed S_L. Where it meets a faster flow it must lean over: sin α = S_L / U. The cone angle is a flame-speed meter.

A Premixed flameFuel and air are mixed before burning; the flame is a travelling wave whose temperature you choose via φ. is a travelling wave. It moves into the fresh mixture at the laminar flame speed SLS_L, a property of the mixture, so where the flow is faster than SLS_L the flame must lean over. The Bunsen cone angle obeys sin⁡α=SL/U\sin\alpha = \cflame{S_L}/\cair{U}: the cone is literally a flame-speed meter. You get to choose its temperature, because you choose φ. Run lean and it is cool and low in NOₓ. But it can FlashbackA flame propagating upstream, against the flow, into hardware not designed to contain it. if the flow ever slows below SLS_L, and it is easy to shake into oscillation (Lesson 7).

A Diffusion flameFuel and air meet in the flame and burn where they reach stoichiometric proportions — robust, but always at the hottest surface. has no speed of its own. Fuel and air arrive separately and burn wherever they meet in stoichiometric proportion, so the flame sits on the hottest possible surface, whatever the overall mixture. It cannot flash back, it is extremely stable, and it is simple. That is why conventional aero combustors are diffusion-flame devices. The price is high peak temperatures (NOₓ) and fuel-rich pockets on the fuel side (soot, the yellow glow).

Chemistry-limited or mixing-limited?

One more distinction is worth making before we build a combustor around this flame. Combustion can be slow for two very different reasons:

  • Chemically limited: fuel and air are mixed, but it is too cold (or too low in pressure) for the reactions to go fast. Think cold starts, idle, altitude. The fix is temperature, pressure or time.
  • Mixing limited: the chemistry would be instant, but fuel and oxygen haven't met yet. This is typical of a diffusion flame at high power. The fix is better aerodynamics: more turbulence, better atomisation, smarter jets.

Diagnosing which regime you are in tells you which lever will actually help. Adding fuel to a mixing-limited flame just makes it longer and smokier.

The master trade-off

If you raise the flame temperature…Consequence
↑ Reaction rateShorter, more efficient combustor
↑ Stability marginWider operating envelope, easier relight
↑ Thermal NOₓ (exponentially)Worse emissions
↑ Heat load on the linerShorter hardware life

Everything that follows, from swirlers and fuel staging to cooling and RQL, is ultimately a strategy for navigating this table.

Recap
What to carry forward
  • The equivalence ratio ϕ\phi measures mixture strength against stoichiometric: lean < 1 < rich.
  • Adiabatic flame temperature is a bell curve in ϕ\phi, peaked slightly rich, and lifted by inlet preheat.
  • Arrhenius: rates scale like e−Ea/RTe^{-E_a/RT}, so small temperature changes cause huge rate changes. Temperature is the master variable.
  • Premixed flames let you choose a cool temperature, but risk flashback and instability. Diffusion flames are robust, but always burn at the stoichiometric peak.
  • Slow combustion is either chemistry-limited (fix with T, P or time) or mixing-limited (fix with aerodynamics).

Next: the very first component the air meets. Before the flame can be anchored, the diffuser must slow the air from ~150 m/s without throwing away the pressure the turbine needs.

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Up next · Lesson 3DiffusersHow do you slow air down without throwing away pressure?Keep going →