Lesson 9 of 15

Gas Power Systems

Air-standard cycles for internal-combustion engines and gas turbines: Otto, Diesel and Brayton; why compressor work dominates a gas turbine, how regeneration, intercooling and reheat help, and how a combined cycle stacks a steam plant under a gas turbine to pass 60%.

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The question

A car engine squeezes a cylinder of air, burns fuel in it with a bang, and lets it push a piston, thousands of times a minute. A jet engine does the same three things — compress, burn, expand — but continuously, in a stream of air flowing through spinning blades. Why do jet engines and car engines work so differently?

The air-standard idealisation

In a gas power system there is no closed working fluid: air comes in, fuel is burned inside it, and exhaust goes out. To analyse such engines with the tools of cycles, Moran and Shapiro use the air-standard analysis:

  • The working fluid is a fixed mass of air, treated as an ideal gas.
  • Combustion is replaced by heat transfer from an external source.
  • The exhaust and intake are replaced by heat rejection to the surroundings, closing the cycle.
  • All processes are internally reversible.

With constant specific heats evaluated at room temperature, this is the cold-air standard: approximate, but it reveals what controls efficiency with a minimum of algebra.

Spark and squeeze: Otto and Diesel

A reciprocating engine is characterised by its compression ratio r=Vmax/Vminr = V_\text{max}/V_\text{min} and its mean effective pressure — the constant pressure that, acting over the stroke, would give the same net work.

The Otto cycleThe ideal cycle of a spark-ignition engine, with heat added at constant volume. Its efficiency depends only on the compression ratio. idealises the petrol engine: isentropic compression, heat added at constant volume (the spark ignites a premixed charge that burns almost instantly at top dead centre), isentropic expansion, heat rejected at constant volume. Its cold-air efficiency depends only on the compression ratio:

ηOtto=1−1rγ−1.\eta_\text{Otto} = 1 - \frac{1}{r^{\gamma - 1}}.

The Diesel cycleThe ideal cycle of a compression-ignition engine, with heat added at constant pressure. idealises the compression-ignition engine: air alone is compressed until it is hot enough to ignite fuel injected near top dead centre, and the fuel burns as it is sprayed in — roughly at constant pressure while the piston moves down.

ExploreSpark or squeeze?
00.20.40.60.8023456890113specific volume v (m³/kg)pressure (bar)Otto (petrol)r = 9.5 · η = 59.4%end of compression 738 Kpeak 3245 K · 103 barMEP 13.9 barDieselr = 18.0 · η = 59.4%end of compression 953 Kpeak 2744 K · 57 barMEP 13.1 bar
9.5
18.0
1800 kJ/kg air
more fuel → more heat
Otto efficiency59.4%1 − 1/r^(γ−1)
Diesel efficiency59.4%
Challenges0/3
  • Give the petrol engine the highest efficiency you can without knock.
  • Find a case where the Otto cycle beats the Diesel cycle.
  • Notice that the Diesel’s efficiency falls as you add more fuel at fixed r. Push it below 58% at r = 18.
Air-standard Otto (petrol, spark ignition: heat added at constant volume) and Diesel (compression ignition: heat added at constant pressure) cycles, with the same heat input per kilogram of air and cold-air properties (γ = 1.4). The petrol engine’s compression ratio is limited by knock; the diesel’s is not.

At the same compression ratio, the Otto cycle wins: all its heat goes in at the highest temperature. But a petrol engine cannot raise its compression ratio much above 10–12, because the premixed fuel–air charge would ignite on its own and knock. The diesel compresses only air, so it has no such limit — it needs 15–22:1 just to ignite its fuel — and that is why diesels are more efficient in practice.

Check your intuition
In the widget, a diesel's efficiency falls as you add more fuel (more heat per cycle) at a fixed compression ratio. Why?

The Brayton cycle: the gas turbine

A gas turbine does the same thing in a continuous flow. The Brayton cycleThe ideal cycle of a gas turbine: compressor, combustor (constant pressure), turbine, heat rejection (constant pressure). idealises it: isentropic compression in a compressor, heat addition at constant pressure in a combustor, isentropic expansion through a turbine, and (in the closed idealisation) heat rejection at constant pressure. With cold-air properties the efficiency depends on the pressure ratio:

ηBrayton=1−1rp(γ−1)/γ.\eta_\text{Brayton} = 1 - \frac{1}{r_p^{(\gamma-1)/\gamma}}.

Moran and Shapiro's Example 9.4 — ten-to-one pressure ratio, 1400 K turbine inlet — gives 45.7% with variable properties; the lab reproduces it.

LabThe gas-turbine engine
0.00.51.01.5200600100014001800s − s₁ (kJ/kg·K)temperature (K)inlet 300 Kcompressor exit 574 Kturbine exit 787 K020400%20%40%60%pressure ratioefficiency vs pressure ratioturbine work706 kJ/kgcompressor work280 kJ/kgnet work427 kJ/kg
10.0
1400 K
100%
none
Thermal efficiency45.7%
Back-work ratio40%compressor ÷ turbine
Net work427 kJ/kg2.3 kg/s of air per MW
Exhaust787 K513 °C
Challenges0/3
  • Find realistic settings (≤ 88% components) where the compressor uses more than 60% of the turbine work.
  • Reach 40% with 88% components and no regenerator.
  • Use regeneration to reach 45% at a pressure ratio below 8 with 88% components.
The Brayton cycle with air properties that vary with temperature. Left: the cycle on the T–s diagram (entropy relative to the inlet air). Right: thermal efficiency against pressure ratio for the current settings, with the current point. Toggle a regenerator, intercooling and reheat to see how each reshapes the cycle.

The striking number is the Back work ratioThe fraction of the turbine work consumed by the pump or compressor: about 1% in a steam plant, 40–60% in a gas turbine.. Compressing a gas is expensive (Lesson 4), and the compressor of a gas turbine typically consumes 40–60% of the turbine's work. That makes the whole machine brutally sensitive to component efficiencies: a few points lost in the compressor or turbine come straight out of a much smaller net work. Gas turbines became practical only in the 1940s, when aerodynamics and metallurgy finally made both components good enough.

Hence the obsession with turbine inlet temperature. Higher T3T_3 means more turbine work for the same compressor work. Modern machines run their first-stage blades in gas at 1600–1900 K, well above the melting point of their nickel alloys, kept alive by internal cooling passages and ceramic coatings.

Regeneration, intercooling and reheat

  • Regeneration. At modest pressure ratios, the turbine exhaust is hotter than the compressed air. A heat exchanger, the regenerator, uses the exhaust to preheat the air before the combustor, cutting the fuel needed. At high pressure ratios the exhaust is cooler than the compressed air, and regeneration is useless.
  • Intercooling. Compressing in two stages with cooling in between reduces the compressor work, since cooler gas has a smaller vv and w=∫v dpw = \int v\,dp.
  • Reheat. Expanding in two stages with a second combustor in between increases the turbine work.

Intercooling and reheat raise the net work; on their own they lower the efficiency, because they add heat at lower temperatures and reject it at higher ones. Combined with regeneration, they push the cycle toward the Ericsson cycle, which has the Carnot efficiency.

Estimate first
A large gas turbine at 40% efficiency produces 300 MW. Roughly how much air flows through it, in kg/s, if its net work is 400 kJ per kg of air?
1101001,00010,000100,000
Drag along the line to place your guess — each tick is ten times the last.

Jet engines

An aircraft gas turbine is a Brayton cycle in which the turbine produces only enough work to drive the compressor; the rest of the gas's enthalpy is expanded in a nozzle to make a fast jet. A turbofan uses part of the turbine work to drive a large fan, accelerating a lot of air gently, which is far more propulsively efficient. The thermodynamics is the same; the product is thrust instead of shaft power.

Combined cycles: the best of both

A gas turbine receives its heat very hot — over 1600 K — but throws its exhaust away at 850–900 K. A steam plant rejects its heat beautifully cold, near 300 K, but can only take heat in below about 900 K. Put them together and you get a cycle that receives heat at the gas turbine's temperatures and rejects it at the steam plant's:

LabTwo engines, one fuel
095191286382477300400500600700800900heat transferred (kJ per kg of gas)temperature (K)pinch 10 Kgas-turbine exhaust 867 Kstack 418 Kboiling at 311 °C
18.0
1600 K
100 bar
540 °C
10 K
smaller = bigger, costlier boiler
Gas turbine alone41.9%
Combined cycle58.8%steam adds 29% of the power
Steam per kg of gas144 g
Challenges1/3
  • Push the combined cycle above 55%.
  • Reach 60% — today’s best plants are just above it.
  • Widen the pinch until the stack is hotter than 450 K, and see what a cheaper boiler costs in efficiency.
A combined-cycle plant: a gas turbine (88% compressor, 90% turbine) exhausts into a heat-recovery steam generator that raises steam for a Rankine cycle. The plot is the boiler’s temperature–heat diagram: gas cooling (orange) and water heating, boiling and superheating (blue). Where the curves come closest — the pinch — limits how much steam the exhaust can raise.

The gas turbine's exhaust flows through a heat-recovery steam generator that raises steam for a Rankine cycle. Overall,

ηcc=ηgt+(1−ηgt) ηboiler ηsteam,\eta_\text{cc} = \eta_\text{gt} + (1 - \eta_\text{gt})\,\eta_\text{boiler}\,\eta_\text{steam},

and two cycles of about 40% and 35% combine to around 60%. The Combined cycleA gas turbine whose hot exhaust raises steam for a steam turbine, reaching efficiencies above 60%. plant is the most efficient way yet devised to make electricity from fuel, and it is what most new gas-fired stations are.

Going deeper
Going deeper: where the cold-air standard misleads

The cold-air standard overestimates both temperatures and efficiencies, often by 5–15 percentage points, because real combustion gases have higher cpc_p (lower γ\gamma) at high temperature, as Lesson 3 showed. Real engines lose more still: heat transfer to cylinder walls, incomplete combustion, valve timing, friction and pumping losses. A petrol engine with r=10r = 10 has an Otto efficiency of 60%, but a brake efficiency of 30–38%; the best large two-stroke marine diesels reach about 55%.

For gas turbines, the variable-property calculation in the lab is already much better than the cold-air one. Its remaining idealisations — no pressure losses in the combustor or ducts, no cooling air bled from the compressor to protect the blades — cost a real engine a few more points.

Recap
What to carry forward
  • Air-standard analysis models internal-combustion engines as cycles of air with heat added and rejected.
  • Otto: constant-volume heat addition, η=1−r1−γ\eta = 1 - r^{1-\gamma}, limited by knock. Diesel: constant-pressure heat addition, higher compression ratios, higher real efficiency.
  • Brayton: η=1−rp−(γ−1)/γ\eta = 1 - r_p^{-(\gamma-1)/\gamma} ideally. The back-work ratio of 40–60% makes gas turbines sensitive to component efficiency and hungry for high turbine inlet temperatures.
  • Regeneration helps at low pressure ratios; intercooling and reheat raise net work.
  • A combined cycle uses gas-turbine exhaust to drive a steam cycle: around 60% efficiency.

Next: run a cycle backwards and it pumps heat uphill. How can a heat pump deliver three units of heat for one of electricity?

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